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fCylinder multi entries? [feature script]

otaolafrotaolafr Member Posts: 113 EDU
hello,
I have to do some cylinders between several points,
is it possible to do in an easier way than doing fCylinder for each pair of points? (i should clarify all of them are the same radius)
for example if i want to do two cylinders from p1 to p2 and from p3 to p4
do something like:
            fCylinder(context, id + "cylinder1", {
                    "topCenter" : p1,p3
                    "bottomCenter" : p2,p4
                    "radius" : definition.r
            });
best regards,
franco
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Best Answer

Answers

  • NeilCookeNeilCooke Moderator, Onshape Employees Posts: 5,308
    If the transform between the points can be calculated, then create one fCylinder and opPattern will be faster. Otherwise, just put fCylinder in a loop.
    Senior Director, Technical Services, EMEAI
  • otaolafrotaolafr Member Posts: 113 EDU
    NeilCooke said:
    If the transform between the points can be calculated, then create one fCylinder and opPattern will be faster. Otherwise, just put fCylinder in a loop.
    thanks!
  • otaolafrotaolafr Member Posts: 113 EDU
    NeilCooke said:
    If the transform between the points can be calculated, then create one fCylinder and opPattern will be faster. Otherwise, just put fCylinder in a loop.
    neil sorry for bothering,
    at the end i used fCylinder for each one without a loop,
    i wanted to boolean in one part,
    i tried:
            opBoolean(context, id + "boolean1", {
                    "tools" : qGeometry(qEverything(), GeometryType.CYLINDER),
                    "operationType" : BooleanOperationType.UNION
            });
    but it doenst work and the error says : invalid input, qGeometry(qEverything(), GeometryType.CYLINDER) would normally select all the cylinders that exist in the context isnt it? what i am missing?
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