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Defining function variables - Function does not work in a certain case
francois_leclerc
Member Posts: 2 ✭
in General
I have defined the following variable (function)
HalfWidth = function (len) { return len *.05 in; }
If I provide a number such as 1, it works fine and I end up with a width of .5
I have another variable WallThickness defined as 0.167 in.
If I provide this variable as a parameter to the HalfWidth function, I get an error message that this is not a valid expression.
I have another function to which I can provide the WallThickness variable and that doesn't pose a problem.
What should I do?
HalfWidth = function (len) { return len *.05 in; }
If I provide a number such as 1, it works fine and I end up with a width of .5
I have another variable WallThickness defined as 0.167 in.
If I provide this variable as a parameter to the HalfWidth function, I get an error message that this is not a valid expression.
I have another function to which I can provide the WallThickness variable and that doesn't pose a problem.
What should I do?
0
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