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# accessing one coordinate of a vector?

Member Posts: 701 PRO
I'm trying to use a triad manipulator to set 3 different length parameters (XY and Z coordinates). Since the base and offset of the triad are both simple vectors I'm not sure how to send the x value to the X length parameter. Is there a way to get one of the values out of a vector? Am I asking the right question? Manipulators in general are new to me too, so any info helps.
Evan Reese / Principal and Industrial Designer with Fractal
Instagram: @evan.reese.designs

• Member, OS Professional, Developers Posts: 1,945 EDU
@Evan_Reese

3d vectors in Onshape are just a simple array of three ValueWithUnits, meaning that you can get the x, y and z dimensions with vec[0], vec[1], and vec[2], respectively.
MB - I make FeatureScripts: View FeatureScripts
• Onshape Employees Posts: 49
You can access the vector as an array to get the x, y, and z components.  Like myVector[0] to get the x component.
The Transform feature uses a triad manipulator, you can take a look at the transformManipulatorChange method in transformCopy.fs in the standard library.  I've copied the relevant portion here:
const offset = input[TRANSLATION].offset;
output.dx = offset[0];
output.dy = offset[1];
output.dz = offset[2];
You can also use the dot product, like dot(myVector, (vector(1, 0, 0))), which would get the x component of myVector.

• Member, OS Professional, Developers Posts: 1,945 EDU
@Evan_Reese

3d vectors in Onshape are just a simple array of three ValueWithUnits, meaning that you can get the x, y and z dimensions with vec[0], vec[1], and vec[2], respectively.
MB - I make FeatureScripts: View FeatureScripts
• Onshape Employees Posts: 49
You can access the vector as an array to get the x, y, and z components.  Like myVector[0] to get the x component.
The Transform feature uses a triad manipulator, you can take a look at the transformManipulatorChange method in transformCopy.fs in the standard library.  I've copied the relevant portion here:
const offset = input[TRANSLATION].offset;
output.dx = offset[0];
output.dy = offset[1];
output.dz = offset[2];
You can also use the dot product, like dot(myVector, (vector(1, 0, 0))), which would get the x component of myVector.

• Member Posts: 701 PRO
I'm really glad it's that simple. I thought that's what I'd tried but I must have not had it quite right. I've got it working now.
Evan Reese / Principal and Industrial Designer with Fractal